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Timken bearings has a web site where you can calculate the frequency of the bearing roller, cup, and cone vibration based upon the failure type and the bearing cone speed.
First, calculate the rotational speed of the suspected bearing cone. The bearing cone speed is typically the speed of the component it is connected to. For example, a pinion gear bearing cone will turn the same speed as the pinion gear. The pinion gear rotates the same speed as the propshaft connected to it.
Third, click here to go to the Timken bearing vibration frequency calculator. Enter the bearing part number and the cone speed. The frequency calculator will show the vibration frequencies of the bearing roller, cup, and cone at that speed.
The Timken pinion bearing (HM88649) shown above has 17 taper roller bearings attached to the cone (inner race), it takes 2.476 revolutions of the cone (inner race) to have all 17 rollers make their way around the cup (outer race). According to the Timken calculations for the HM88649 bearing:
A roller with one irregularity (Nick or Spall) would have a vibration frequency of 1.0 Hz at 8.738 cone RPM. By converting shakes per second (Hz) to shakes per minute (Hz x 60) the roller irregularity would vibrate 60 times for every 8.738 revolutions of the cone. (60 shakes/minute) / (8.738 revolutions/minute) = 6.687 shakes per revolution. So, a roller with one irregularity on it's bearing contact surface results in a vibration equal to a 6.867 order propshaft speed related vibration.
A cone with one irregularity (Nick or Spall) would have a vibration frequency of 1.0 Hz at 6.212 cone RPM. By converting shakes per second (Hz) to shakes per minute (Hz x 60) the cone irregularity would vibrate 60 times for every 6.212 revolutions of the cone. (60 shakes/minute) / (6.212 revolutions/minute) = 9.659 shakes per revolution. So, a cone with one irregularity on it's bearing contact surface results in a vibration equal to a 9.659 order propshaft speed related vibration.
A cup with one irregularity (Nick or Spall) would have a vibration frequency of 1.0 Hz at 8.176 cone RPM. By converting shakes per second (Hz) to shakes per minute (Hz x 60) the cup irregularity would vibrate 60 times for every 8.176 revolutions of the cone. (60 shakes/minute) / (8.176 revolutions/minute) = 7.339 shakes per revolution. So, a cup with one irregularity on it's bearing contact surface results in a vibration equal to a 7.339 order propshaft speed related vibration.

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